When measuring time constant its C x R (CAPICITANCE TIMES RESISTOR)?

If i have a 2k ohm resistor for instance and 100uF capacitor


the sum would be ? (i'm not sure if this it right please verify)





2000x100uF x 10-3 = 200





Is this the correct way of working out the time constant.

When measuring time constant its C x R (CAPICITANCE TIMES RESISTOR)?
"the sum would be". you mean "the product would be"





2000Ω x 100µF


2000 x 100 x 10^-6


200000 x 10^-6


0.2 seconds
Reply:2^3 * 100 ^-6 = 0.2 sec

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