Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 68 miles in the same time that Dana travels 62 miles. If Chuck's rate of travel is 3 mph more than Dana's, and they travel the same length of time, at what speed does Chuck travel?
C and D agree to meet in Chicago.C travels 68 miles in the same time that D travels 62 miles.?
Okay for this problem you're going to use the equation d = r * t, where d is distance (in miles), r is rate (mph), and t is time. Given two distances and two rates, with equal length of time, you first solve for time and set the two equations equal to each other. These are your knowns.
Chuck d = 68 miles
Dana d = 62 miles
Chuck r = x + 3 mph
Dana r = x
t = d/r for both
The equations you would set equal to each other are d1/r1 = d2/r2
So 68/(x+3) = 62/x.
To solve you would cross-multiply.
68x= 62(x+3)
Then you would solve for x
68x = 62x + 186
6x = 186
x = 31
Therefore Dana is travelling at x = 31 mph, and Chuck is travelling at x+3 or 34mph.
HTH
Reply:34mph
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