Monday, July 27, 2009

C and D agree to meet in Chicago.C travels 68 miles in the same time that D travels 62 miles.?

Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 68 miles in the same time that Dana travels 62 miles. If Chuck's rate of travel is 3 mph more than Dana's, and they travel the same length of time, at what speed does Chuck travel?

C and D agree to meet in Chicago.C travels 68 miles in the same time that D travels 62 miles.?
Okay for this problem you're going to use the equation d = r * t, where d is distance (in miles), r is rate (mph), and t is time. Given two distances and two rates, with equal length of time, you first solve for time and set the two equations equal to each other. These are your knowns.





Chuck d = 68 miles


Dana d = 62 miles


Chuck r = x + 3 mph


Dana r = x


t = d/r for both





The equations you would set equal to each other are d1/r1 = d2/r2





So 68/(x+3) = 62/x.


To solve you would cross-multiply.





68x= 62(x+3)


Then you would solve for x


68x = 62x + 186


6x = 186


x = 31





Therefore Dana is travelling at x = 31 mph, and Chuck is travelling at x+3 or 34mph.





HTH
Reply:34mph


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